Wednesday, April 30th 2008, 8:34pm
Quoted
make the QtextEdit item public
If I do this it's the same as making a public function in Window 1 that writes to the TextEdit. My problem is that I don't know how to access Window 1's content, the QTextEdit or the function.
create a friend class for the second window with the first.
I'm sorry but I don't know what a friend class is.
let window 1 be parent to window 2 and post items from window 2 to the parent
How do I do this?
Thanks
Thursday, May 1st 2008, 7:27am
Hello,
Here is the solution of your problem...
jst use this application hope this will work for u..
Here is the solution of your problem...
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Source code |
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#include <QObject>
#include <QApplication>
#include <QLabel>
#include <QPushButton>
#include <QWidget>
#include <QDialog>
#include <QTextEdit>
class MainWindow : public QWidget
{
Q_OBJECT
public:
QTextEdit *textEdit;
MainWindow( QWidget *parent = 0 );
public slots:
void setTextInMainWindow();
};
MainWindow::MainWindow( QWidget *parent):QWidget( parent )
{
textEdit = new QTextEdit(this);
//QDialog *dialog = new QDialog( 0 );
}
void MainWindow::setTextInMainWindow()
{
//MainWindow tempWin;
textEdit->setPlainText("My Text");
qWarning( "My Text" );
}
class MyDialog : public QDialog
{
Q_OBJECT
public:
QPushButton *pb;
MyDialog( QWidget *parent = 0 );
//public slots:
// void setTextInMainWindow( const QString );
};
MyDialog::MyDialog( QWidget *parent):QDialog( parent )
{
pb = new QPushButton("&Click", this);
//QDialog *dialog = new QDialog( 0 );
}
#include "Hello.moc"
int main( int argc, char *argv[] )
{
QApplication app( argc, argv );
MainWindow tempWindow;
MyDialog dialog;
QObject::connect( dialog.pb, SIGNAL( clicked()), &tempWindow, SLOT( setTextInMainWindow() ) ) ;
dialog.show();
tempWindow.show();
return app.exec();
}
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jst use this application hope this will work for u..
Regards
Kunal Nandi
Kunal Nandi